Let us solve linear programming word problems
Let us take 2 variables x and y to represent the number of chairs & tables respectively.
Hence the price of x tables = 1200x & the price of y chairs = 500y.
Here the total investment cannot be more than 50,000, therefore,
The total price = 1200x + 500y ≤ 50,000. This is the 1st constraint inequality.
Here, hence the storage capacity is for 100 pieces, we have x + y ≤ 100. This is the 2nd constraint equation. Hence the number of chairs & the number of tables non-negative, we have x ≥ 0, y ≥ 0.
Now, profit on y chairs = 75y. & the profit on x tables is 180 xs
Here, the objective is to maximize the profit, so the objective function is 180x + 75y.
Hence the linear programming model is given by:
Maximize Z = 180x + 75y
Subject to the constraints
1200x + 500y ≤ 50,000
x + y ≤ 100
x ≥ 0, y ≥ 0.
In our next blog we shall learn about partial fraction calculator I hope the above explanation was useful.Keep reading and leave your comments.
Let us take 2 variables x and y to represent the number of chairs & tables respectively.
Hence the price of x tables = 1200x & the price of y chairs = 500y.
Here the total investment cannot be more than 50,000, therefore,
The total price = 1200x + 500y ≤ 50,000. This is the 1st constraint inequality.
Here, hence the storage capacity is for 100 pieces, we have x + y ≤ 100. This is the 2nd constraint equation. Hence the number of chairs & the number of tables non-negative, we have x ≥ 0, y ≥ 0.
Now, profit on y chairs = 75y. & the profit on x tables is 180 xs
Here, the objective is to maximize the profit, so the objective function is 180x + 75y.
Hence the linear programming model is given by:
Maximize Z = 180x + 75y
Subject to the constraints
1200x + 500y ≤ 50,000
x + y ≤ 100
x ≥ 0, y ≥ 0.
